Question

A stone in droppes from the roof of a building it takes 4sec to reach the ground.Find the height of the building

Answer 1

$\textbf{ Hello Mate! }$

Given : u = 0 ( rest )

a = 10 m/s^2

t = 4 s

By 2nd equation if motion we get,

$s = ut + \frac{1}{2} a {t}^{2} \\ s = (0)(4) + \frac{1}{2} (10) {(4)}^{2} \\ s = 0 + \frac{1}{2} \times 10 \times 4 \times 4 \\ s = 80 \: m$

Hence, height of building is 80 m.

$\textsf{ \red{ Answer is 80 m }}$

Have great future ahead!

Answer 2

Here is your solution

Given:-

U=0

a = 10 m/s^2

time = 4 sec

For finding distance we used 2nd equation of motion.

s = ut+ 1/2at^2

s=0×4+1/2×10×4^2

s=0+1/2×10×16

s=80m

The height of the building is 80m

Note:-

S=distance.

T=time.

a=acceleration.

u= initial velocity.

Hope it helps you