Question

A stone is allowed to fall from the top of 1000 m
high tower. What will be its speed after 2 second
and with speed will it hit the ground ?
(a) 4.9 ms -1, 49.8 ms
(b) 19.6 ms, 140 m srl
(c) 17.6 m sl, 176 m srl
(d) 39.2 ms, 210 ms​

Answer 1

Answer:

u=0

distance=1000

v after 2 seconds

v=u +at

v=0+9.8*2

v=19.6m/s

v at ground

v2=u2+2as

v2=0+2*9.8*1000

v^2=19600

v=140m/s