A stone is allowed to fall from the top of a cliff 1000m high.1.what will be its speed after 2 sec?2.with what speed will it hit the ground.
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u =0
s= 1000m
g = 9.8m/s^2
..
1..... t =2s
v= u+at
v= 0+9.8×2
v= 0+ 19.6
v= 19.6m/s
..
2
..
2as = v^2 -u^2
2×9.8×1000 = v^2 - (0)^2
19600 = v^2
140 =v
s= 1000m
g = 9.8m/s^2
..
1..... t =2s
v= u+at
v= 0+9.8×2
v= 0+ 19.6
v= 19.6m/s
..
2
..
2as = v^2 -u^2
2×9.8×1000 = v^2 - (0)^2
19600 = v^2
140 =v
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