Physics, asked by raghav4141, 2 months ago

A stone is allowed to fall from the top of a tower 100 m high and at the same time a stone is projected vertically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet.(Take g = 10m/s²).

Answers

Answered by tasneemthegirl

Explanation:

Answer Expert Verified

(100-S) = distance travelled by the projected stone. Therefore, Two stones will meet after 4 s. = 80 m. Thus , both the stone will meet at a distance of 80 m from the top of tower

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A stone is allowed to fall from the top of a tower 100 m high and at the same time a stone is projected vertically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet.(Take g = 10m/s²).​

Answers

A stone is allowed to fall from the top of a tower 100 m high and at the same time a stone is projected vertically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet.(Take g = 10m/s²).