A stone is allowed to fall from the top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet.
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Explanation:
(100-S) = distance travelled by the projected stone. Therefore, Two stones will meet after 4 s. = 80 m. Thus , both the stone will meet at a distance of 80 m from the top of tower.
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0
Answer:
(100-S) = distance travelled by the projected stone. Therefore, Two stones will meet after 4 s. = 80 m. Thus , both the stone will meet at a distance of 80 m from the top of tower.
Explanation:
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