A stone is allowed to fall from the top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet.
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Explanation:
Let t be the point at which two stones meet and let h be their height from the ground.
Height of the tower is H = 100 m (Given)
It is clear from the question that we need to calculate time when the two stones met. After calculating time, we will also be able to calculate the distance.
Now, first consider the stone which falls from the top of the tower.
Initial velocity (u) = 0
So, distance covered by this stone at time t can be calculated using equation of motion
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