A stone is allowed to fall from the top of a tower 100m high and at the same time another stone is projected vertically upward from the ground with a velocity 25m/s. Calculate when and where the two stones will meet.
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Answer:
(100-S) = distance travelled by the projected stone. Therefore, Two stones will meet after 4 s. = 80 m. Thus , both the stone will meet at a distance of 80 m from the top of tower
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(100 - S) = distance traveledled by the projected stone. Therefore, two stones will meet after 4 S. = 80 m. Thus, both the stone will meet at a distance of 80 m from the top of tower.
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