Question

A stone is allowed to fall from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground​

Answer 1

$\huge\mathtt{★\:Solution\: :-}$

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$\tt{Initial \:Velocity\: u\:=\:0}$

$\tt{Final \:velocity \:v\:=\:?}$

$\tt{Height,\: s\:=\:19.6m}$

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$\tt{By\: third\: equation\: of \:motion\: :-}$

$\orange{⇻}$$\tt{v}^{2}$ $\tt{=}$$\tt{u}^{2}+\:2gs$

$\orange{⇻}$$\tt{v}^{2}$$\tt{=\:0\:+\:2\:×\:9.8\:×\:19.6}$

$\orange{⇻}$$\tt{v}^{2}$$\tt{=\:384.16}$

$\orange{⇻}$$\tt{v\:=\:19.6m/s}$

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$\sf\pink{Answer\:⇝}$$\tt\purple{19.6\: m/s}$

Answer 2

Answer:

19.6m/s

Explanation:

v2=u2+2as=0+2(9.8)(19.6)

v=19.6m/s