Question

A stone is allowed to fall from the top of tower 100 metre high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25ms−1. The two stones will meets after​

Answer 1

hope this will help u

Answer 2

Given,

Distance = 100 m

Velocity = 25 m/s

Now, When stone dropped from Tower.

=> S = ut + 1/2 gt^2

=> S = 0 + 1/2 x 10 x t^2

=> S = 5t^2 ----------- (1)

Again, When stone projected upward.

=> 100-S = ut - 1/2 gt^2

=> 100-S = 25t - 1/2 x 10 x t^2

=> 100-S = 25t - 5t^2

=> 100- 25t +5t^2 = S

=> S = 100-25t+5t^2 --------- (2)

Adding both equations:-

S = 100-25t+5t^2
- S = 5t^2
_________________________
=> 0 = 100-25t

=> 25t = 100

=> t = 100/25

=> t = 4s


Hence, Both stone will meet after 4s