A stone is allowed to fall on atop of tower of height 100m calculate its final velocity of a the stone if it takes 1 min to reach the ground gravity is 10m/s square
Answers
Answered by
1
We can use Newton's laws of motion
v²-u²=2gs
v²=2as,. since u=0
v²=2.10.100
v²=2000
v=√2000=10√20
v²-u²=2gs
v²=2as,. since u=0
v²=2.10.100
v²=2000
v=√2000=10√20
Satwatneyearthian:
plz mark as brainliest
Answered by
1
Given :
u = 0
H = 100 m
t = 1 min = 60 sec
g = 10m/s^2
v = ?
By applying first equation of motion ;
v = u+gt
v = 0+10×60
v = 600 m/s
u = 0
H = 100 m
t = 1 min = 60 sec
g = 10m/s^2
v = ?
By applying first equation of motion ;
v = u+gt
v = 0+10×60
v = 600 m/s
I think that u is not equal to zero
why
it is just dropped and made to free fall
because the question is not following second equation of motion ; S=ut+1/2gt^2
plz help me
the question is wrong it cannot fall down in one minute it willtake mare time
less time
sorry
Similar questions