a stone is doppped from a top of abuilding 122.5 metre high after 1 sec another stone is thrown downwords such that the both of them hits the ground simultaneously calculate thier time fall and velocity with which they hits the ground
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Answer:
Time of fall is approx 2.94s
Explanation:
Use equation of motions
aditi9850:
which egn of motion we put
S=ut +1\2at^2
i am not able to find the ans
can u show me how to find the answer
since the body is in free fall, use S=122.5m and u=0 and a=g=9.8 and then use that above eqation to find time
okay thanks
my pleasure!
but what's the velocity
velocity of first ball 49m/s and second ball 72.65m/s
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