a stone is drooped from top of the tower. the distance travelled by stone in first second is (neglect the air resistance take G=10ms^-2
Answers
Answered by
0
Answer:
5m
Explanation:
a stone is drooped from top of the tower. the distance travelled by stone in first second is (neglect the air resistance take G=10ms^-2
Stone is dropped
=> initial Velocity u = 0 m/s
a = g = 10 m/s²
Distance S = ut + (1/2)at²
t = 1 sec
S = 0*1 + (1/2)(10)1²
=>S = 0 + 5
=> S =5 m
the distance traveled by stone in first second is 5 m
Similar questions