Physics, asked by bharghav4, 1 year ago

a stone is drooped from top of the tower. the distance travelled by stone in first second is (neglect the air resistance take G=10ms^-2​

Answers

Answered by amitnrw
0

Answer:

5m

Explanation:

a stone is drooped from top of the tower. the distance travelled by stone in first second is (neglect the air resistance take G=10ms^-2​

Stone is dropped

=> initial Velocity u = 0 m/s

a = g = 10 m/s²

Distance S = ut + (1/2)at²

t = 1 sec

S = 0*1 + (1/2)(10)1²

=>S = 0 + 5

=> S =5 m

the distance traveled by stone in first second is 5 m

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