a stone is droped don a deep well from rest. the well is 50 meter deep. how long will it take to reach the bottom of the well. given a=9.8 ms-2
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h = 50m
t = √2h/g = √2×50/9.8 = √100/9.8 = 3.19 second
it will take 3.19 second to reach the bottom of well.
t = √2h/g = √2×50/9.8 = √100/9.8 = 3.19 second
it will take 3.19 second to reach the bottom of well.
Answered by
1
h = 50m
t = √2h/g = √2x50/9.8 = √100/9.8 = 3.19 second
it will take 3.19 second to reach the bottom of well.
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