A stone is dropped down a deep well from rest the well is 50m deep .how long will it take to reach the bottom of the well? (given a=9.8m/s sq
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Hey
Here is your answer
====================================
given
u=0m/s
a=9.8m/s^2
s=50m
now s=ut+1/2at^2
50=0(t)+1/2*9.8*t^2
50/4.9=t^2
t^2=10.20
t=3.19s
====================================
HOPE IT WILL HELP
PLEASE MARK IT AS BRAINLIEST
Here is your answer
====================================
given
u=0m/s
a=9.8m/s^2
s=50m
now s=ut+1/2at^2
50=0(t)+1/2*9.8*t^2
50/4.9=t^2
t^2=10.20
t=3.19s
====================================
HOPE IT WILL HELP
PLEASE MARK IT AS BRAINLIEST
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