Question

A stone is dropped down a deep well from rest. The well is 50 m deep. How long will it take for the stone to reach the bottom of the well. (given g = -10m/ s2). guys pls help urgent it is. guys pls help i wil give you 8 points.. guys pls pls hel[ mewith it u just say how to do this . pls help and i will give u 8 points for sure but make it fast pls

Answer 1

$\sf{\boxed{\boxed{\green{ANSWER:}}}} \sf \: t = 3.16seconds$

$\sf{\boxed{\boxed{\pink{GIVEN:}}}}$

$\sf{height = 50m} \\ \sf{ g = - 10m \ {s}^{-2}} \\ \sf{v = 0}$

$\sf{\boxed{\boxed{\blue{TO\: FIND:}}}}$

$\sf \: t = ??$

$\sf{\boxed{\boxed{\red{FORMULA}}}}$

$\sf \: { {v}^{2} - u}^{2} = 2as \\ \sf \: v = u + at$

$\sf{\boxed{\boxed{\purple{EXPLANATION:}}}}$

$\sf \: {0}^{2} - {u}^{2} = 2( - 10) \times 50$

$\sf \: {u}^{2} = 1000$

$\sf \: u = \sqrt{1000} = 10 \sqrt{10}$

$\sf u= 10(3.16)m {s}^{ - 1}$

$\sf \: u = 31.6 - 10t$

$\sf \: 10t = 31.6$

$\sf \: t = 3.16seconds$

Hence it takes 3.16s to reach the bottom of the well.

Answer 2

Given that ,

" A stone is dropped down a deep well from rest. The well is 50 m

deep. How long will it take for the stone to reach the bottom of the well.

( given g = - 10 m/ s² ) "

So ,

Initial velocity , u = 0 m/s

Distance , s = - 50 m [ Due to upwards ]

Time , t = ? s

Acceleration due to gravity , a = - 10 m/s²

Use 2nd equation of motion ,

⇒ s = ut + ¹/₂ at²

⇒ s = 0 (t) + ¹/₂ gt²

⇒ - 50 = ¹/₂ ( -10 ) t²

⇒ - 50 = - 5 t²

⇒ 5 t² = 50

⇒ t² = 10

⇒ t = 3.16 s

So , Time taken for the stone to reach the bottom of the well is 3.16 seconds.