Question

a stone is dropped down a deep well from rest. the well is 50 metre Deep. how long will it take to reach the bottom to the well? Given a=9.8 m s2​

Answer 1

Answer:

Given,

u=0 m/s

S=50 m

g=9.8 m/(s^2)   (for freely falling body,g is +ve)

t=?

For a freely falling body dropped from rest,

S=1/2g*t^2    (S=ut+1/2a*t^2=>S=0+1/2g*t^2=>S=1/2g*t^2)

50=1/2*9.8*t^2

t^2=50*2/9.8

t^2=10.204

=>t=(10.204)^1/2

=>t=3.19 sec

hence,it will take 3.19 sec to reach bottom of the well.

Answer 2

Answer:

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