a stone is dropped down a deep well from rest the well is 50 metre deep. how long will it take to reach the the bottom of the well ?given acceleration 9.8 m/s²
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Answer:
Given, hieght of the well = 50 m.
acceleration due to gravity = 9.8 m/s^2.
s = ut + 1/2 at^2
initial velocity u, = 0
50 = 1/2 × 10 × t^2
t^2 = 100 / 9.8
t = √ 10.2
t = 3.19 seconds
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