Question

a stone is dropped down at the well from rest the well is 50 m deep for long how long will it takes to reach the bottom of the well given a is equal to 9.8 metre per second square​

Answer 1

Answer :-

We know that ,

v=0.5×gt

s/t=0.5×gt

s=0.5×g×t×t

50=0.5×9.8×t×t

t^2=50/4.9

t=3.194

Answer 2

Answer:

S= ut+ 1/2 a t^2

S= ut+ 1/2 a t^250=1/2 at^2

S= ut+ 1/2 a t^250=1/2 at^2take a=g= 10m/s

S= ut+ 1/2 a t^250=1/2 at^2take a=g= 10m/s10= t^2

S= ut+ 1/2 a t^250=1/2 at^2take a=g= 10m/s10= t^2t=3.16 sec.