Question

A stone is dropped down from a deep well from rest . the well is 50m deep . how long will it take to reach the bottom of the well? given a=9.8m/s^2​

Answer 1

Answer:

let initial velocity(u)=0 ms-1

a(g) = 9.8 ms-2

d= 50 m

s= ut + 0.5 at ^2

50 = 0(t) + 9.8t^2

50 = 9.8X t^2

t^2  = 2.258

t = 1.5026

t = 1.5 s

Answer = 1.50 s