Question

A stone is dropped freely from certain height. The velocity acquired by the stone in 4seconds is ____ (Take g = 9.8 ms-2)

Answer 1

Answer:

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Explanation:

Given, a=g=10m/s

2

t=4s

u=0m/s {Initial velocity at rest}

So, height= ut+

2

1

at

2

=(0)(u)+

2

1

(10)(16)

=80m

∴ Height of the tower= 80m .

Answer 2

Answer:

v=u+at

t=4

a=9.8

u=0 (since it is freely falling body)

v=0+(4×9.8)

v=39.2ms-1

the velocity acquired by the stone after 4 seconds is 39.2 ms-1