Question

A stone is dropped freely from the top of a tower and reaches the ground in 10s.Taking g=10 m/s^2, calculate the height of the tower
80m
160m
500m
1000m​

Answer 1

Answer:

The height of the tower is 500 m.

Given:

• A stone is dropped freely from the top of a tower and reaches the ground in 10 s.

• g = 10 m/s².

To find:

• Height of the tower.

Formula:

s = ut + ½ at²

(Second equation of motion)

Calculation:

For body in free fall,

Initial velocity (u) = 0,

Acceleration (a) = Acceleration due to gravity = g

Here, Time (t) = 10 s

By using formula,

$\boxed{\sf{s=ut+\dfrac{1}{2}\times \ at^{2}}}$

⠀⠀=> s = 0 (t) + ½ (10) (10)²

⠀⠀=> s = 5 (100)

⠀⠀=> s = 500 m

Therefore, the height of the towers is 500 m.

______________________________

Extra information:

• Equation of motion for free fall

1. v = gt
2. s = ½ gt²
3. v² = 2gs

• Equation of motion for body moving vertically upward.

1. u = gt
2. s = ut - ½ gt²
3. u² = 2as