a stone is dropped freely ina river from a bridge. it takes 5s to touch the water surface in the river. calculate :(i) the height of the bridge from the water level,(ii) the distance covered by the stone in the first 2s ( g= 9.8ms-2).
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i)given
u=0
t=5s
a=g=9.8m/s
we know that s=ut+1/2gt^2
therefore,
s=0×5+1/2×9.8^2=9.8m/s
u=0
t=5s
a=g=9.8m/s
we know that s=ut+1/2gt^2
therefore,
s=0×5+1/2×9.8^2=9.8m/s
histoyuvi:
hekl
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