Question

A stone is dropped from a 100m high tower how long does it take to fall

Answer 1

Answer:

v=u+at

v=0+9.8t

v=9.8t

t=v/9.8

now,s=ut + 1/2 at2

=100=1/2×98×v/98×v/9.8

=v2 = 1960

v2-v2 = 2as

-1960=. 2×2

-1960/4

= a0

490m/s

Answer 2

Answer:

for the first 50m

U is 0

and v is =

v^2=u^2+2as

v^2=0+2*10*50=1000

v=10√10

now t=v-u/t=(10√10-0)/t

therefore t= 10√10/10=√10s=3.34s

approx......

Explanation:

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