A stone is dropped from a 500m tall building into a pond, when is sound splash heard? given g= 10m/s2 speed of sound=340m/s
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S=500m
g=a=10m/s^2
U=0 m/s
V^2-u^2=2as
V^2=2×500×10
V^2=10000
V=10000root= 100m/s
Speed at which stone hit the water+ speed for sound to reach us=Time taken for us to hear it
Time taken for us to hear it=100+ (500/340)= 100 + 1.47= 101.47 m/so
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g=a=10m/s^2
U=0 m/s
V^2-u^2=2as
V^2=2×500×10
V^2=10000
V=10000root= 100m/s
Speed at which stone hit the water+ speed for sound to reach us=Time taken for us to hear it
Time taken for us to hear it=100+ (500/340)= 100 + 1.47= 101.47 m/so
Put a thanks if it helps you and mark me as the brainliest
Answered by
4
given height,s=500m
g=10
speed of sound =340
on analysing we get that we have to find time period
first analyze the data and apply different formulas for it then see which formula suits the best.
the formula that should be used here is
s=ut+1/2at2
u=0,
500=0+1/2x10xtxt
we get t=10 sec
now the time for the resound=500/340=1.47 sec
total time=10+1.47=11.47 sec
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