Question

A stone is dropped from a balloon at an altitude of 300m . how long the stone

Answer 1

We will use the kinematic equations.

We have :

S = ut + 1/2gt²

u = 0 => initial velocity

g = 10 = > Acceleration due to gravity.

S = Distance / height = 300m

t = time

Substituting in the formula :

300 = 0 + 1/2 × 10 × t²

300 = 5t²

60 = t²

√60 = 7.76 seconds

7.76 Seconds.

Answer 2

Answer:

The time will be 7.8 sec.

Explanation:

Given that,

Height h = 300 m

Using equation of motion

$s= ut+\dfrac{1}{2}gt^2$.....(I)

Here, u = initial velocity

t = time

g = acceleration due to gravity

s = height

Now, Put the value of h in equation (I)

$300= 0+\dfrac{1}{2}\times9.8t^2$

$t^2=\dfrac{300}{4.9}$

$t= \sqrt{\dfrac{300}{4.9}}$

$t= 7.8\ sec$

Hence, The time will be 7.8 sec.