A stone is dropped from a balloon going up with a uniform velocity of 5 m/s. If the balloon was 60 m high when the stone was dropped, find its height when the stone hits the ground.
Answers
Answered by
0
Answer:
ANSWER
s=ut+
2
1
at
2
−60=5(t)+
2
1
(−10)t
2
−60=5t−5t
2
5t
2
−5t−60=0
t
2
−t−12=0
t
2
−4t+3t−12=0
(t−4)(t+3)=0
∴t=4
Height of balloon from ground at this instant
=60+4×5=80 m
Similar questions