Question

a stone is dropped from a balloon going up with a uniform velocity of 5 metre per second. if the balloon was 50 M high when the stone was dropped, and its height when the stone hits the ground.

Answer 1

the height of balloon from ground will become 70m

Answer 2

Answer:

The height when the stone hits the ground is 51.2 m.

Explanation:

Given that,

Initial velocity u = 5 m/s

Height h= 50 m

Using equation of motion

$v= u+gt$....(I)

here, u = initial velocity

v = final velocity

g = acceleration due to gravity

t = time

Put the value of all element in equation (I)

$0=5+9.8\times t$

$t= 0.5\ s$

The height when the stone hits the ground

Again using equation of motion

$s=ut-\dfrac{1}{2}gt^2$

$s=5\times0.5-\dfrac{1}{2}\times9.8\times (0.5)^2$

$s= 1.2\ m$

The height of the balloon will be

$H= h+h'$

$H= 50+1.2=51.2\ m$

Hence, The height when the stone hits the ground is 51.2 m.