A stone is dropped from a balloon going up with a uniform velocity of 10 m/s. If the height of the balloon was 56.25 m when the stone was dropped, then the time after which the stone will strike the ground after it is dropped is [10m/s]
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use s=ut+ at^2/2; u=10m/s; a= -10m/s^2; t=?
u can find t=4.5s
put it in v=u+at; u=10m/s; a= -10; t=4.5
solve to get final velocity of stone.
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