Question

A stone is dropped from a balloon going up with a uniform velocity of 5 m/s. If the balloon was 60 m high when the stone was dropped, find its height when the stone hits the ground.

Answer 1

please see attached file......

Answer 2

$\underline\bold{Answer}$

By using Equation :

$s \: = ut \: + \frac{1}{2} a {t}^{2} \\ \\ - 60 = 5t + \frac{1}{2} ( - 10) {t}^{2} \\ \\ 5 {t}^{2} - 5t - 60 = 0 \\ \\ {t}^{2} - t - 12 = 0 \\ \\ {t}^{2} - 4t + 3t - 12 = 0 \\ \\ (t - 4)(t + 3) = 0 \\ \\ t = 4$

Height of balloon from the ground at this instant = 60 +4×5

= 80 m

$\underline\bold{Thanks}$