A stone is dropped from a balloon rising upwards with a velocity of 16m/s.the stone reaches the ground in 4 sec
Answers
Answered by
11
Suppose t1 is the time taken to reach to the maximum height and t2 is the time taken to come to ground from maximum height.
Now,
We know that v=u−gt=0 or t=u/g=16/9.8=1.63 s
Now the body has travelled tor the ground in,
(4-1.63)=2.37 seconds.
So using the formula,
Total height h is,
h=1/2gt^2
=12×9.8×2.37^2=27.52 m.
Again the upward distance travelled by the balloon is,
h1=ut−1/2gt^2
=16×1.63−1/2×9.8×1.63^2
=13.06 m.
So the height of the balloon is (27.52−13.06)=14.46 m
Now,
We know that v=u−gt=0 or t=u/g=16/9.8=1.63 s
Now the body has travelled tor the ground in,
(4-1.63)=2.37 seconds.
So using the formula,
Total height h is,
h=1/2gt^2
=12×9.8×2.37^2=27.52 m.
Again the upward distance travelled by the balloon is,
h1=ut−1/2gt^2
=16×1.63−1/2×9.8×1.63^2
=13.06 m.
So the height of the balloon is (27.52−13.06)=14.46 m
Answered by
13
Answer:
Answer is given above.
Attachments:
Similar questions