A stone is dropped from a bridge and it reaches the ground in 4 seconds. The height of the bridge is (g = 10 m/s)
O 80 m
O 64 m
0 260 m
O 2000 m
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Answer:
80m
Explanation:
initial velocity (U) = 0
acceleration by gravity (g) = 10 m/s^2
time (t) = 4 seconds
h = ut+1/2at^2
h= 1/2(160)
h=80m
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