a stone is dropped from a building of height 30m.it accelerates at the rate of 10m/s. what will be the velocity of the stone when it hits the ground?how long will it take to reach the ground
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Answer:
As a ball is dropped,it’s initial velocity u=o.
height, s=30.
a=10
final velocity, v=?.
time taken, t=?.
now,
as from the formula of final velocity, v=(2gh)^1/2
v=(2*10*30)^1/2
v=(600)^1/2
v=24.4 m/sec………This is the final velocity
we also know that v=u+at
24.4=0+(10)(t)
t=2.44 sec …. This the time taken
Explanation:
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