Question

A stone is dropped from a building of height 9.6m. The time taken by it to reach the ground is.

NO IRRELEVANT ANSWERS ALLOWED

Answer 1

Answer:

Explanation:

The stone is not given any initial vertical velocity, so we will assume it falls freely under gravity.

Using kinematics formula we have

$d = ut + 0.5at^{2}$

Here u = 0

a = g = 9.8 $m/s^2$

t = required time to reach the ground

Therefore,

$9.6 m = 0.5*9.8*t^2$

this gives us

$t^2 = 1.959$

Which gives us

t = 1.399 seconds

We can approximate this as the time for reaching the ground is 1.4 seconds.