Question

a stone is dropped from a certain height which can reach the ground in 5 seconds it is stopped after 3 seconds of its fall and then it is again release the total time taken by the stone to reach the ground will be

Answer 1

since , Hmax=1/2gt^2
displacement=Hmax=125m
as it is said that..the stone was stopped after 3 sec of its fall.
then, displacement=1/2gt^2=45m
therefore , remaining distance = (125-45)=80m
now. by using eq. of motion
s=ut+1/2gt^2
80=0+1/2×10×t^2
16=t^2
4=t
therefore, total time taken by the stone to reach at the ground = 4sec.

Answer 2

Answer:

Explanation:

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