A stone is dropped from a cliff 100m what will be its final velocity before touching ground
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Answer:
s=100 m u=0 a= 10 m/s^2
Explanation:
by third equation of motion v^2-u^2= 2(a)(s) v^2-0^2=2(10)(100)
v^2=2000 v=20√5 m/s
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