Question

A stone is dropped from a cliff calculate its speed after it has fallen a t m

Answer 1

Answer:

$v \: = \: \sqrt{2gt}$

Explanation:

${v}^{2} = \: {u}^{2} + \: 2gt$

now, u=0

so,

${v}^{2} = \: 2gt$

so,

$v \: = \: \sqrt{2gt}$

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