A stone is dropped from a height 100m at what speed it will hit the ground
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u=0
a=9.8m/s^2
h=100m
v=?
so apply the third equation of motion
v^2=u^2+2as
=0+2×9.8×100
=1,960
=√1960
=14√10m/s
a=9.8m/s^2
h=100m
v=?
so apply the third equation of motion
v^2=u^2+2as
=0+2×9.8×100
=1,960
=√1960
=14√10m/s
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