Question

A stone is dropped from a height h. Arrive at an expression for the time taken to reach the ground

Answer 1

Answer:

u can calculate the time taken by it from 3rd equation of motion ,

s = ut + at^2/2

given the stone is dropped so its initial velocity(u) is 0 , s = h

so ,

h = 0(t) + at^2/2

h = at^2/2

2h = at^2

√[2h/a ] = t

∴ time taken by it to reach ground is √[ 2h/a]

hope it helps u!!!!!