A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground is changed by
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The momentum when it hits the ground is changed by 41%
Explanation:
velocity (v) = √2gh ............ i
momentum (p) = mv ........... ii
Equation i and ii gives
p∝ √h
now,
p2/p1 = √h2/h1
p2/ P1 = √2h / h
= √2
p2 = 1.414 p1
% change = p2-p1/p1 X 100
= 41%
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