A stone is dropped from a height h . Simultaneously another stone is thrown up from the ground with such a velocity that it can reach a height 4h . Find the time when two stone cross each other .
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Explanation:
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SOLUTION
u is the velocity with which second stone is projected.
At heighest point v= 0
s= 4h
a= -g
0- u^2 = -2g4h
u= √8gh
Let t is the time when they cross each other.
In t time distance travel by first stone is:
Distance travelled by second stone is:
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