Question

A stone is dropped from a height of 100 m on Earth. At the same time, another stone is

thrown vertically upwards from the ground with a velocity of 25 ms-1

. At what time &

height from the ground will the two stones meet?
​

Answer 1

Answer:

a1 = +g = +0 ms-21

Explanation:Another stone B is projected upwards from the ground with an initial velocity u2 = 25ms-1 and for it a2 = -g = -10 ms-2

Let the two stones meet at a point C at a distance y below A or (100-y) above B after a time t.