a stone is dropped from a height of 20m what will be its speed when it hits the ground? ( g=10m/sec square or root 2)
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Speed of stone when it hits the ground, v = 20 m/s
Explanation:
According to the questions,
Initial velocity of a the stone , u = 0 ( dropped from height )
Height, h = 20 m
Acceleration due to gravity,
g = 10m/s square
Therefore, by using Third Equation of Motion :
v^2 - u^2 = 2gh
we get,
v^2 - 0^2 = 2 × 10 x 20
v^2 = 400
v = 20 m/s i.e. speed with which stone hits the ground.
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