Physics, asked by thiyamronaldo64, 7 months ago

A stone is dropped from a height of 49 m and simultaneously another ball is
thrown upwards from the ground with a speed of 40 m/s. When and where do
the two stones meet?​

Answers

Answered by jamunagovind1978
0

Answer:

You mentioned this speed of 40m/s because this is the speed that the stone which is thrown from a height of 49m will reach when it touches the ground. which gives: t=49/40=1.225 second

Explanation:

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Answered by rohinpranav1215
1

Answer:

1.225seconds

Explanation:

You mentioned this speed of 40m/s because this is the speed that the stone which is thrown from a height of 49m will reach when it touches the ground. which gives: t=49/40=1.225 second.

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