A stone is dropped from a height of 49 m and simultaneously another ball is
thrown upwards from the ground with a speed of 40 m/s. When and where do
the two stones meet?
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0
Answer:
You mentioned this speed of 40m/s because this is the speed that the stone which is thrown from a height of 49m will reach when it touches the ground. which gives: t=49/40=1.225 second
Explanation:
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Answered by
1
Answer:
1.225seconds
Explanation:
You mentioned this speed of 40m/s because this is the speed that the stone which is thrown from a height of 49m will reach when it touches the ground. which gives: t=49/40=1.225 second.
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