a stone is dropped from a height of 490m, from the ground. it will hit the ground after
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Answered by
1
Given h=s=490m
initial velocity = 0
acceleration= 9.8m/s² (acceleration due to gravity)
t=?
W.K.T. s = ut+1/2at²
490= 0+ 1/2*9.8*t²
490= 4.9*t²
t²= 100
t = 10s
Therefore, the stone will hit the ground after 10 seconds.
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Answered by
0
s=h=490m
u=0
g=9.8m/s
t=?
s=1/2gt^2
490=1/2(9.8)t^2
490=4.9t^2
490/4.9=t^2
rootof100=t
t=10seconds
u=0
g=9.8m/s
t=?
s=1/2gt^2
490=1/2(9.8)t^2
490=4.9t^2
490/4.9=t^2
rootof100=t
t=10seconds
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