Question

a stone is dropped from a height of 50m calculate it velocity just before it touches the ground (take g=10m/s^2​

Answer 1

thanks

Explanation:

Distance (s) =20 m

Initial velocity =0 m/s

g=10 m/s

2

By using the formula:

v

2

=u

2

+2as

v

2

=0

2

+2×10×20

v

2

=400

v

2

=

400

v=20m/s

For calculating time:

V=u+at

20=0+10×t

t=

10

20

t=2 sec

The the stone will hit the ground with a velocity of 20 m/s in sec.

sorry but i got of 20 m and not 50m