Physics, asked by Shivani22119, 8 months ago

A stone is dropped from a height of 80 m. Find

(i) Time of fall
.
(ii) Velocity after 2 seconds of free fall
.
(iii) Velocity with which it hits the ground.​

Answers

Answered by Anonymous
5

Answer:

Explanation:

u = 0, s= 80 , a =10

80 = 1/2 x 10 x t^2 ---------- t = 4 seconds

v = 20m/s ( after 2seconds)

v = 40 m/s (after 4 seconds.)

Answered by ayushbag03
3

Answer:

u = 0, s= 80 , a =10

80 = 1/2 x 10 x t^2 ---------- t = 4 seconds

v = 20m/s ( after 2seconds)

v = 40 m/s (after 4 seconds.)

Hope it helps

Mark as ,"Brilliant"..

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