A stone is dropped from a height of 80 m. Find
the time taken by stone to cover this distance
and velocity with which it hit the ground.
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Given;
Distance(height)=80m
Therefore, using equation 2nd of motion,
s=ut+(1/2)at², we get;
80=(0)(t)+(1/2)(10)(t²)
=>80=(1/2)(10)(t²)
=>80=(5)(t²)
=>80/5=t²
=>16=t²
=>√16=t
t=4s
Therefore, time taken by the object to reach the ground is 4 seconds.
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