a stone is dropped from a height rest. the height of the well is 50 m. how long will it take to reach the ground..... given a= 9.8m/s
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U=0
S=50m
A=9.8m/s²
S=UT+1/2at²
50=1/2×9.8t²
50=4.9t²
50/4.9=t²
500/49=t²
√500/√49=t
√500/7=t
10√5/7=t
(ÆÑẞWĒR)
#Mærk ãß thē Bråìñlïêßt
Rëgārdß
Tèàm Káñçhâ
S=50m
A=9.8m/s²
S=UT+1/2at²
50=1/2×9.8t²
50=4.9t²
50/4.9=t²
500/49=t²
√500/√49=t
√500/7=t
10√5/7=t
(ÆÑẞWĒR)
#Mærk ãß thē Bråìñlïêßt
Rëgārdß
Tèàm Káñçhâ
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