Question

A stone is dropped from a height such that in 10sit reaches ground.
Find the ratio of distance covered in first and last second of its
motion?

WRITE CORRECTLY FOR BRAINLIEST

Answer 1

Given :-

Height = 10 sit reaches ground

To Find :-

Ratio of 1st and last second

Solution :-

We know that

$\sf \star s = ut + \dfrac{1}{2} a t^{2}$

Let the ratio be S/S'

S/S' =[ 0(1) + 1/2 + g(1)^2]/[1/2 g(10)^2 - 1/2 g(9)^2]

S/S' = [0 + 1/2 + g]/[1/2 + g (100 - 81)]

S/S' = [g/2]/[g/2 (19)]

S/S' = 1:19