Question

A stone is dropped from a height. Wht will be the energy that will be possessed by the body at any point before reaching the ground?​

Answer 1

Answer:

linear motion:

y = y0 + vt + (1/2)gt

assuming y0 and v are initially 0:

90 = (1/2)gt^2

t^2 = 180 / 9.8

t = 4.3s

The velocity at t = 4.3s:

v = v0 + gt

v = 0 + 9.8 * 4.3 = 42m/s

Explanation:

As the stone is falling, it’ll speed up due to gravity. Let's call that acceleration g. On the Earth’s surface (i.e. at sea level) and even 90 m above it, it'll be roughly true that the free falling stone will speed up by 9.81 m/s each second. (You can look up this value online.) In short, its acceleration is roughly a steady, unchanging:

g = 9.81 m/s every second.

Answer 2

Answer: kinetic energy, potential energy

Explanation:It is bcuz KE is possessed by a body due to virtue of its motion. And potential energy due to the height. Since vertically downward projected body has both it posses bot